Mathematics College
Answers
Answer 1
Determine the volume of each rectangular or triangular prism round to the nearest tenth if necessary
____________________
volume = base (B)* height (H)
_____________________
Base area
Triangle
B = b*h/2
Rectangle
B= L1*L2
__________________
volume = base (B)* height (H)
H= 15
Triangle case
B = 4.8 *9.6 /2
B = 46.08 / 2
B= 23.04
V= 23. 04* 15
V= 345.6 in ^3
Related Questions
identify the slope: 6x - 2y = -6
Answers
Answer:
The slope = 3
Explanations:
Note that:
The slope - Intercept form of the equation of a line takes the form y = mx + c
where m is the slope and
c is the intercept
The given equation is:
6x - 2y = -6
The equation can be re-written as:
2y = 6x + 6
2y / 2 = 6x/2 + 6/2
y = 3x + 3
The slope, m = 3
The intercept, c = 3
Slope m=3
Y intercept=3
Which function rule would help you find the values in the table?J K2 -124 -246 -368 -48A k=-12jB k=-6jC k=j - 12D k=j - 6
Answers
Solution
As seen from the table
For each values of the table
We define the variation from K to J
[tex]\begin{gathered} K\propto J \\ K=cJ\text{ (where c is constant of proportionality)} \end{gathered}[/tex]
When J = 2, K = -12
[tex]\begin{gathered} K=cJ \\ -12=c(2) \\ 2c=-12 \\ c=-\frac{12}{2} \\ c=-6 \end{gathered}[/tex]
Therefore, the formula connecting them will be
[tex]k=-6j[/tex]
Option B
A person randomly selects one of four envelopes. Each envelope contains a check that the person gets to keep. However, before the person can select an envelope, he or she must pay $ 15 to play. Determine the person's expectation if two of the envelopes contain $ 5 checks and two of the envelopes contain $ 35 checks.
Answers
The person's expectation if two of the envelopes contain $ 5 checks and two of the envelopes contain $ 35 checks is $5.
In the given question,
A person randomly selects one of four envelopes.
Each envelope contains a check that the person gets to keep.
However, before the person can select an envelope, he or she must pay $15 to play.
We have to determine the person's expectation if two of the envelopes contain $5 checks and two of the envelopes contain $35 checks.
As we know that when the person have to select envelope then they have to pay $15.
Total number of envelop = 4
From the 4 envelop 2 have $5 each and 2 have $35 each.
So the probability of getting envelop of $5 = 2/4 = 1/2
Probability of getting envelop of $35 = 2/4 = 1/2
Let x be the amount a person gets after selecting the envelop.
So E(x) = $5×1/2 + $35×1/2
Taking 1/2 common on both side
E(x) = 1/2 ($5+$35)
E(x) = 1/2×$40
E(x) = $20
But he have to pay $15 before selecting the envelop.
So required expectation = $20−$15 = $5
Hence, the person's expectation if two of the envelopes contain $ 5 checks and two of the envelopes contain $ 35 checks is $5.
To learn more about Probability link is here
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How do you slove this promblem 207.4÷61
Answers
we have
207.4÷61
[tex]207.4\div61=\frac{207.4}{61}=\frac{2,074}{610}=\frac{1,830}{610}+\frac{244}{610}=3+\frac{244}{610}=3\frac{244}{610}[/tex]
simplify
244/610=122/305=4/10=2/5
therefore
the answer is 3 2/5
A circle and two distinct lines are drawn on a sheet of paper what is the largest possible number of points of intersection of these figures (it is Q29)
Answers
Answer:
C 5
Step-by-step explanation:
The two lines can both intersect the circle twice, and can intersect each other once, so 2 + 2 + 1 = 5
Please assist me. I have no idea how to start this equation
Answers
Part a
Remember that the linear equation in slope-intercept form is
y=mx+b
where
m is the slope or unit rate
b is the y-intercept or initial value
In this problem
the equation is of the form
C=m(n)+b
where
m=8.50
b=350
therefore
C=8.50n+350
Part b
A reasonable domain for n (number of cups)
Remember that the number of cups cannot be a negative number
so
the domain is the interval [0, infinite)
but a reasonable domain could be [0, 500]
Find out the range
For n=0 -----> C=350
For n=500 ----> C=8.50(500)+350=2,100 ZAR
the range is the interval [350,2,100]
Part c
calculate the cost
For n=100 cups ----> C=8.50(100)+350=1,200 ZAR
For n=200 cups ----> C=8.50(200)+350=2,050 ZAR
For n=400 cups ---> C=8.50(400)+350=3,750 ZAR
Part d
Average cost
Divide the total cost by the number of cups
For 100 cups ------> 1,200/100=12 ZAR per cup
For 200 cups ----> 2,050/200=10.25 ZAR per cup
For 400 cups ----> 3,750/400=9.38 ZAR per cup
Part e
it is better to order more cups, to reduce the initial ZAR 350 cost.
Part f
In this problem we have the ordered pairs
(200, 2150) and (400, 3750)
Find out the slope m
m=(3750-2150)/(400-200)
m=8 ZAR per cup
Find out the linear equation
C=mn+b
we have
m=8
point (200,2150)
substitute and solve for b
2150=8(200)+b
b=2150-1600
b=550
therefore
The linear equation is
C=8n+550
Part g
A reasonable domain could be [0, 600]
Find out the range
For n=0 ------> C=550
For n=600 ----> C=8(600)+550=5,350
The range is the interval [550,5350]
Part h
The gradient is the same as the slope
so
slope=8
that means ----> the cost of each cup is 8 ZAR
Part i
For n=600
C=8(600)+550=5,350 ZAR
Part j
we have the inequality
8n+550 < 8.50n+350
Solve for x
550-350 < 8.50n-8n
200 < 0.50n
400 < n
Rewrite
n > 400
For orders more than 400 cups is more effective to order from Cupomatic
Verify
For n=401
C=8n+550=8(401)+550=3,758 ZAR
C=8.50n+350=8.5(401)+350=3,758.5 ZAR
the cost is less in CUPOMATIC, is ok
the answer is
For orders more than 400 cups is more effective to order from Cupomatic
In solving for the inverse function for y = sqrt(3x + 2) - 1 , which of the following represents the first step?
Answers
we know that
The first step to find out the inverse of the function is to exchange the variables (x for y and y for x)
therefore
the answer is the second option
a 14-member board used for admitted
Answers
Using the Borda's method, when one person is ranked as 1st, he/she gets 3 points, if he/she is ranked 2nd, get 2 points, also, if he/she is ranked as 3rd get 1 point, and finally, 0 points if she/he is ranked as 4th
so, let's detemine how many points got each one
Cardona: Was selected 1st by 6 people, 2nd by 2 people, 3rd by 4 people and 4th by 2 people
[tex]C=3*6+2*2+1*4=26[/tex]
So, that's a total of 26 points
Pitts-Jones: Was selected as: #1 by 4 people, #2 by 3 people, #3 by 6 people and 4th by 1 person
[tex]P=3*4+2*3+1*6=24[/tex]
So, that's 24 points for Pitts-Jones,
De Plata: Was ranked #1 by 2 people, #2 by 8 people, #3 by 1 person and #4 by 3 people
[tex]D=3*2+2*8+1*1=23[/tex]
That's 23 points for De Plata
Vincent: Was ranked as #1 by 2 people, #2 by 1 person, #3 by 3 people and #4 by 8 people
[tex]V=3*2+2*1+1*3=11[/tex]
that's 11 points for Vincent,
Answer: From the above, we can conclude that the winner using Borda's method is Cardona
Order the numbers from least (1) to greatest (10).ITEM BANK-Move to Battom3.564.034.212V12mor
Answers
To order these numbers, we begin with the whole part of each number. In the case of having two numbers with equal whole part, we look for the greatest tenth. So, the order would be
[tex]3.56;4.03;4.2;12[/tex]
Notice that, 4.03 is less than 4.2, because its tenth is less.
Surface area of a cone: S = πr² + πrl;solve for l.
Answers
Answer:
[tex]l=\frac{S-\pi r^{2}}{\pi r}[/tex]
Explanation:
The surface area of a cone is calculated using the formula:
[tex]S=πr^2+πrl[/tex]
We want to solve for l.
First, subtract πr² from both sides of the equation:
[tex]\begin{gathered} S-\pi r^2=\pi r^2-\pi r^2+\pi rl \\ S-\pi r^2=\pi rl \end{gathered}[/tex]
Next, divide both sides by πr:
[tex]\begin{gathered} \frac{S-\pi r^2}{\pi r}=\frac{\pi rl}{\pi r} \\ l=\frac{S-\pi r^{2}}{\pi r} \end{gathered}[/tex]
The equation solved for l is:
[tex]l=\frac{S-\pi r^{2}}{\pi r}[/tex]
The Max or Min can be found by using the line of symmetry. That line of symmetry can be found by finding the midpoint of the two x-intercepts.Since the line of symmetry is x =-1 Write the function rule to find the coordinate to the minimum of this parabola.[tex]f (x) = (x - 2)(x + 4)[/tex]your answer should be in the form (_,_)
Answers
We know that, for a parabola, the minimum, or the maximum, is given by the vertex of the parabola. The formula for the vertex of the parabola is given by:
[tex]x_v=-\frac{b}{2a},y_v=c-\frac{b^2}{4a}[/tex]
And we have the coordinates for x and y for the vertex.
We can see that the line of symmetry is x = -1, and this is the same value for the value of the vertex for x-coordinate, that is, the x-coordinate is equal to x = -1.
With this value for x, we can find the y-coordinate using the given equation of the parabola:
[tex]f(x)=(x-2)\cdot(x+4)\Rightarrow f(-1)=(-1-2)\cdot(-1+4)\Rightarrow f(-1)=(-3)\cdot(3)[/tex]
We can also expand these two factors, and we will get the same result:
[tex]f(x)=(x-2)\cdot(x+4)=x^2+2x-8=(-1)^2+2\cdot(-1)-8=1-2-8=-1-8=-9[/tex]
Therefore, the value for the y-coordinate (the value for the y-coordinate of the parabola, which is, at the same time, the minimum point for y of the parabola) is:
[tex]f(-1)=(-3)\cdot(3)\Rightarrow f(-1)=-9[/tex]
The minimum point of the parabola is (-1, -9) (answer), and we used the given function (rule) to find the value of the y-coordinate.
We can check these two values using the formula for the vertex of the parabola as follows:
[tex]f(x)=(x-2)\cdot(x+4)=x^2+2x-8[/tex]
Then, a = 1 (it is positive so the parabola has a minimum), b = 2, and c = -8.
Hence, we have (for the value of the x-coordinate, which is, at the same time, the value for the axis of symmetry in this case):
[tex]x_v=-\frac{2}{2\cdot1}\Rightarrow x_v=-1[/tex]
And for the value of the y-coordinate, we have:
[tex]y_v=c-\frac{b^2}{4a}\Rightarrow y_v=-8-\frac{2^2}{4\cdot1}=-8-\frac{4}{4}=-8-1\Rightarrow y_v=-9[/tex]
Choose Yes or No to tell whether the expressions are equivalent. 4(5c + 3) and 9c + 7 10f – 10 and 2(8f - 5) 12g + 21 and 3(4g + 7)6(4j – 6) and 24 - 36j
Answers
Answer:
Explanation:
Part 1:4(5c + 3) and 9c + 7
[tex]4\mleft(5c+3\mright)=20c+12\neq9c+7[/tex]
The answer is NO.
Part 2: 10f – 10 and 2(8f - 5)
[tex]2\mleft(8f-5\mright)=16f-10\neq10f-10[/tex]
The answer is NO.
Part 3: 12g + 21 and 3(4g + 7)
Part 4: 6(4) – 6) and 24 - 36
An insurance company offers flood insurance to customers in a certain area. Suppose they charge $500 fora given plan. Based on historical data, there is a 1% probability that a customer with this plan suffers aflood, and in those cases, the average payout from the insurance company to the customer was $10,000.Here is a table that summarizes the possible outcomes from the company's perspective:EventFloodPayout Net gain (X)$10,000 -$9,500$0$500No floodLet X represent the company's net gain from one of these plans.Calculate the expected net gain E(X).E(X) =dollars
Answers
The given is a discrete random variable.
For a discrete random variable, the expected value is calculated by summing the product of the value of the random variable and its associated probability, taken over all of the values of the random variable.
It is given that the probability of a flood is 1%=0.01.
It follows that the probability of no flood is (100-1)%=99%.
Hence, the expected net gain is:
[tex]E(X)=0.01(-9500)+0.99(500)=-95+495=400[/tex]
Hence, the expected net gain is $400.
The expected net gain is E(X) = $400.
please help 50 points!
Answers
Measure of angle 1 is 94 degrees
Measure of angle 2 is 86 degrees
Measure of angle 3 is 94 degrees
A museum curator counted the number of paintings in each exhibit at the art museum. Number of paintings Number of exhibits 9 2 21 1 40 1 1 46 3 52 1 67 2 X is the number of paintings that a randomly chosen exhibit has. What is the expected value of x Write your answer as a decimal.
Answers
Answer
Expected number of paintings that a randomly chosen exhibit has = 40.3
Explanation
The expected value of any distribution is calculated as the mean of that distribution.
The mean is the average of the distribution. It is obtained mathematically as the sum of variables divided by the number of variables.
Mean = (Σx)/N
x = each variable
Σx = Sum of the variables
N = number of variables
Σx = (9 × 2) + (21 × 1) + (40 × 1) + (46 × 3) + (52 × 1) + (67 × 2)
Σx = 18 + 21 + 40 + 138 + 52 + 134
Σx = 403
N = 2 + 1 + 1 + 3 + 1 + 2 = 10
Mean = (Σx)/N
Mean = (403/10) = 40.3
Hope this Helps!!!
How do you solve the system of equations by graphing? y=-3x/2 + 6y=5x - 7
Answers
The given system of equations are
y=-3x/2 + 6
y=5x - 7
We would substitute values for x into the equations and find the corresponding y values. These values would be plotted on a graph. Where the lines of both equations meet would represent the solution of the system of equations.
For the first equation,
y = - 3x/2 + 6
if x = 0, y = 3 * 0/2 + 6 = 6
If x = 1, y = - 3 * 1/2 + 6 = 4.5
if x = 2, y = - 3 * 2/2 + 6 = 3
We would plot these values on the graph
For the second equation,
y = 5x - 7
if x = 0, y = 5 * 0 - 7 = - 7
If x = 1, y = 5 * 1 - 7 = - 2
if x = 2, y = 5 * 2 - 7 = 3
We would plot these values on the graph
The diagram of the graph is shown below
Looking at the graph, at the point where both lines meet,
x = 2, y = 3
Thus, the solution is (2,3)
Question 23 of 25
What is the effect on the graph of f(x) = when it is transformed to
g(x) = +17?
A. The graph of f(x) is shifted 17 units down.
B. The graph of f(x) is shifted 17 units to the right.
OC. The graph of f(x) is shifted 17 units up.
OD. The graph of f(x) is shifted 17 units to the left.
Answers
Answer:
C. The graph of f(x) is shifted 17 units up.
Step-by-step explanation:
When + is outside the equation, it means up.
P(B) = 2/3P(An B) = 1/6What will P(A) have to be for A and B to be independent?1/211/121/45/6
Answers
P(B) = 2/3
P(An B) = 1/6
What will P(A) have to be for A and B to be independent?
Remember that
Events A and B are independent if the equation P(A∩B) = P(A) · P(B) holds true
substitute given values
1/6=P(A)*(2/3)
solve for P(A)
P(A)=1/4
Use the number line to video to find two other solutions to the inequality 7 + m < 20.
Answers
Answer:
m = 2 and m = 3
Explanation:
To find the solutions to the inequality, we need to isolate m. So, we can subtract 7 from both sides as:
7 + m < 20
7 + m - 7 < 20 - 7
m < 13
Therefore, any number that is less than 13, is a solution of the inequality.
For example: 2 and 3 are solutions of the inequality.
For which equation would x = 12 be a solution?x - 12 = 12x - 24 = 12x - 14 = 2x - 5 = 7
Answers
Explanation
We are required to solve each equation till we arrive at the one that satisfies the "x=12" question.
First equation:
[tex]\begin{gathered} x-12=12 \\ Collect\text{ like terms} \\ x=12+12 \\ x=24 \end{gathered}[/tex]
Second equation:
[tex]\begin{gathered} x-24=12 \\ Collect\text{ like terms} \\ x=12+24 \\ x=36 \end{gathered}[/tex]
Third equation:
[tex]\begin{gathered} x-14=2 \\ Collect\text{ like terms} \\ x=2+14 \\ x=16 \end{gathered}[/tex]
Last equation:
[tex]\begin{gathered} x-5=7 \\ Collect\text{ like terms} \\ x=7+5 \\ x=12 \end{gathered}[/tex]
Hence, the last equation is the solution.
1 Ms. Signer has to buy pencils for her class. She goes to CVS and buys 15 pencils for $2.50. How much did she spend per pencil?*
Answers
She bought pencils for her class. She bought 25 pencils for $2.50 . The amount for each pencil can be computed below
[tex]\begin{gathered} 25\text{ pencils = \$2.50} \\ 1\text{ pencil = ?} \\ \text{cross multiply} \\ \cos t\text{ of each pencil=}\frac{2.50}{25} \\ \text{ cost of each pencil = \$}0.1 \end{gathered}[/tex]
Identify the augmented matrix for the system of equations and the solution using row operations.
Answers
Given:
The system of equation is given as,
[tex]\begin{gathered} 7x-4y=28 \\ 5x-2y=17 \end{gathered}[/tex]
The objective is identify the augmented matrix for the system of equations and the solution using row operations.
Explanation:
The required augmented matrix will be,
Performing the Gauss-Jordan elimination with the following operation,
[tex]R_2=R_2-\frac{5R_1}{7}[/tex]
By applying the operation to the augmented matrix,
To find y :
On equating the second row of the matrix,
[tex]\begin{gathered} \frac{6y}{7}=-3 \\ y=\frac{-3}{\frac{6}{7}} \\ y=\frac{-3\times7}{6} \\ y=\frac{-7}{2} \end{gathered}[/tex]
To find x :
On equating the first row of the matrix,
[tex]\begin{gathered} 7x-4y=28 \\ 7x=28+4y \\ x=\frac{28+4y}{7} \end{gathered}[/tex]
Substitute the value of y in the above equation.
[tex]\begin{gathered} x=\frac{28+4(\frac{-7}{2})}{7} \\ x=\frac{28-14}{7} \\ x=\frac{14}{7} \\ x=2 \end{gathered}[/tex]
Thus the value of solutions are,
[tex]\begin{gathered} x=2 \\ y=-\frac{7}{2}=-3.5 \end{gathered}[/tex]
Hence, option (3) is the correct answer.
7) A math teacher asked 60 randomly selected 7th graders whether they 10 pointsare left handed or right handed. The table below shows the results of thesurveyLeft or Right-Handed?Hand FrequencyLeftRight4218A school has a total of 280 seventh-grade students. Based on the resultsshown in the table above, how manyof those seventh-grade studentswould you expect to be left-handed?A 60B 72C 84D 120
Answers
Answer:
C. 84
Explanation:
First, we will calculate the percentage of left-handed students in the group of 60 that the teacher asked.
So, the percentage is equal to:
[tex]\frac{18}{60}\times100\text{ \% = 30\%}[/tex]
Therefore, 30% of the randomly selected students are left-handed.
Now, we can use this percentage to estimate the number of left-handed students in the group of 280.
Then, 30% of 280 is equal to:
[tex]30\text{ \% }\times280=\frac{30}{100}\times280=84[/tex]
So, the answer is C. 84.
What is the average rate of change of the function f(x) = 2x^2 + 4 over the interval (-4,-1] ?
Answers
The average rate of change is:
[tex]\frac{f(-1)-f(-4)}{-1+4}=\frac{f(-1)-f(-4)}{3}[/tex][tex]f(-1)=2(-1^2)+4=6[/tex][tex]f(-4)=2(-4^2)+4=2(16)+4=36[/tex]
then computing the first formula, the average rate of change of f(x) is
[tex]\frac{6-36}{3}=-10[/tex]
2 dot plots. Both number lines go from 0 to 10. Plot 1 is titled fifth grade. There are 2 dots above 1, 3 above 2, 1 above 3, 4 above 4, 5 above 5, 5 above 6, 2 above 7, 2 above 8, 0 above 9, 0 above 10. Plot 2 is titled seventh grade. There are 2 dots above 0, 2 above 1, 3 above 2, 5 above 3, 5 above 4, 3 above 5, 3 above 6, 1 above 7, and 0 above 8, 9, and 10.
The dot plot shows the number of hours, to the nearest hour, that a sample of 5th graders and 7th graders spend watching television each week. What are the mean and median?
The 5th-grade mean is
.
The 7th-grade mean is
.
The 5th-grade median is
.
The 7th-grade median is
.
Answers
The mean and the median for each data-set are given as follows:
5-th grade students:
Mean: 4.67Median: 5 hours.
7-th grade students:
Mean: 3.46 hours.Median: 4 hours.
Dot plot
A dot plot shows the number of times that each observation appears on a data-set.
Hence the hours of the 5th-graders are as follows:
1, 1, 2, 2, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 7, 7, 8, 8
The mean is the sum of all the numbers of hours divided by the number of students, hence:
Mean = (2 x 1 + 3 x 2 + 1 x 3 + 4 x 4 + 5 x 5 + 5 x 6 + 2 x 7 + 2 x 8)/(2 + 3 + 1 + 4 + 5 + 5 + 2 + 2) = 4.67.
There are 24 elements in the data-set, hence the median is the mean of the 12th and the 13th element, as follows:
Median = (5 + 5)/2 = 5.
Hence the hours of the 7th-graders are as follows:
0,0, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 6, 6, 6, 7.
Hence the mean is:
Mean = (2 x 0 + 2 x 1 + 3 x 2 + 5 x 3 + 5 x 4 + 3 x 5 + 3 x 6 + 1 x 7)/24 = 3.46.
The 12th element is of 3, the 13th of 5, hence the median is:
Median = (3 + 5)/2 = 4.
More can be learned about dot plots at https://brainly.com/question/24309209
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152. ) Find all real x such that square root x + 1 = x - Square root x - 1.
Answers
Given the equation:
[tex]\sqrt[]{x}+1=x-\sqrt[]{x}-1[/tex]
Solving for x:
[tex]\begin{gathered} \sqrt[]{x}+\sqrt[]{x}=x-1-1 \\ 2\sqrt[]{x}=x-2 \end{gathered}[/tex]
Now, we take the square on both sides of the equation:
[tex]\begin{gathered} 4x=x^2-4x+4 \\ 0=x^2-8x+4 \end{gathered}[/tex]
Now, using the general solution of quadratic equations:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]
From the problem, we identify:
[tex]\begin{gathered} a=1 \\ b=-8 \\ c=4 \end{gathered}[/tex]
Then, the solutions are:
[tex]\begin{gathered} x=\frac{-(-8)\pm\sqrt[]{(-8)^2-4\cdot1\cdot4}}{2\cdot1}=\frac{8\pm\sqrt[]{64-16}}{2} \\ x=\frac{8\pm4\sqrt[]{3}}{2}=4\pm2\sqrt[]{3} \end{gathered}[/tex]
But the original equation √(x), so x can not be negative if we want a real equation. Then, the only real solution of the equation is:
[tex]x=4+2\sqrt[]{3}[/tex]
hello, in the picture you can see a graph and my teacher said that the domain and range would be all real numbers possible. could you please help me because I don't understand why.
Answers
The domain is all the values of the independent variable (in this case, x) for which the function is defined.
In this case, as it is indicated with the arrows in both ends, the function continues for greater and smaller values of x.
As there is no indication that for some value or interval of x the function is not defined (a discontinuity, for example), then it is assumed that the function domain is all the real values.
Example function:
We have the function y=1/(x-2)
We can look if there is some value of x that makes the function not defined.
The only value of x where f(x) is not defined is x=2. When x approximates to 2, the value of the function gets bigger or smaller whether we are approaching from the right or from the left.
Then, the function is not defined for x=2. So, the domain of f(x) is all the real numbers different from x=2.
The domain is, by default, all the real numbers, but we have to exclude all the values of x (or intervals, in some cases like the square roots) for which f(x) is not defined.
If p(x) is a polynomial function where p(x) = 3(x + 1)(x - 2)(2x-5)a. What are the x-intercepts of the graph of p(x)?b. What is the end behavior (as x→ ∞, f(x)→?? and as x→ -∞, f (x)→ ??) of p(x))?c. Find an equation for a polynomial q(x) that has x-intercepts at -2, 3⁄4, and 7.
Answers
Hello there. To solve this question, we have to remember some properties about polynomial functions.
Given the polynomial function
[tex]p(x)=3(x+1)(x-2)(2x-5)[/tex]
We want to determine:
a) What are the x-intercepts of the graph of p(x)?
For this, we have to determine the roots of the polynomial function p(x). In this case, we have to determine for which values of x we have
[tex]p(x)=0[/tex]
Since p(x) is written in canonical form, we find that
[tex]p(x)=3(x+1)(x-2)(2x-5)=0[/tex]
A product is equal to zero if at least one of its factors is equal to zero, hence
[tex]x+1=0\text{ or }x-2=0\text{ or }2x-5=0[/tex]
Solving the equations, we find that
[tex]x=-1\text{ or }x=2\text{ or }x=\dfrac{5}{2}[/tex]
Are the solutions of the polynomial equation and therefore the x-intercepts of p(x).
b) What is the end-behavior of p(x) as x goes to +∞ or x goes to -∞?
For this, we have to take the limit of the function.
In general, for polynomial functions, those limits are either equal to ∞ or -∞, depending on the degree of the polynomial and the leading coefficient.
For example, a second degree polynomial function with positive leading coefficient is a parabola concave up and both limits for the function as x goes to ∞ or x goes to -∞ is equal to ∞.
On the other hand, an odd degree function usually has an odd number of factors (the number of x-intercepts in the complex plane) hence the limits might be different.
In this case, we have a third degree polynomial equation and we find that, as the leading coefficient is positive and all the other factors are monoic, that
[tex]\begin{gathered} \lim_{x\to\infty}p(x)=\infty \\ \\ \lim_{x\to-\infty}p(x)=-\infty \end{gathered}[/tex]
That is, it gets larger and larger when x is increasing arbitrarily, while it get smaller and smaller as x is decreasing.
c) To find the equation for a polynomial q(x) that has x-intercepts at -2, 3/4 and 7.
The canonical form of a polynomial of degree n with x-intercepts at x1, x2, ..., xn and leading coefficient equals a is written as
[tex]f(x)=a\cdot(x-x_1)(x-x_2)\cdots(x-x_n)[/tex]
So in this case, there are infinitely many polynomials satisfying this condition. Choosing a = 1, we find that q(x) is equal to
[tex]\begin{gathered} q(x)=(x-(-2))\cdot\left(x-\dfrac{3}{4}\right)\cdot(x-7) \\ \\ \boxed{q(x)=(x+2)\cdot\left(x-\dfrac{3}{4}\right)\cdot(x-7)} \end{gathered}[/tex]
These are the answers to this question.
The scatter plot shows the number of CDs in millions that were sold from 1999 to 2005. Use the points (1999,940) and (2002,805) to find a line of fit for the data. Then use the line of fit to estimate the number of CDs that were sold in 2008
Answers
Based on the given points from the scatter plot on the number of CDs sold in millions, the line of best fit for the data is y = -45x + 90,895
The estimated number of CDs sold in 2008 was 535 CDs.
How to find the line of best fit?
The line of best fit will take the form:
y = Slope(x) + y intercept
The value of x will be assumed to be the number of years since 1999.
The slope is:
= Change in y / Change in x
= (805 - 940) / (2002 - 1999)
= -45
The y intercept is:
940 = -45(3) + y
y = 90,895
The line of best fit is:
y = -45x + 90,895
This means that the number of CDs sold in 2008:
= -45(2008) + 90,895
= 535 CDs
Find out more on the line of best fit at https://brainly.com/question/17013321
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Identify all points and line segments in the picture below.Points: A, B, C, DLine segments: AB, BC, CD, AD, BD, ACPoints: A, B, C, DLine segments: AD, AC, DC, BOPoints: A, B, C, DLine segments: AB, AD, AC, DC, BCPoints: A, BLine segments: AB, AC, DC, BC
Answers
Option C
Points: A, B, C, D
Line segments: AB, AD, AC, DC, BC